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If the number is (2^8\times3^5\times5^4\times11^2), by which smallest number should it be divided to make a perfect cube?
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Answer and explanation
Correct answer: (2^2\times3^2\times5\times11^2)
Step 1: For a perfect cube, exponents should be multiples of 3. Step 2: Reduce 8 to 6, 5 to 3, 4 to 3, and 2 to 0 for the smallest divisor. Step 3: So the divisor is (2^2\times3^2\times5\times11^2).
Frequently asked questions
What is the correct answer to this question?
(2^2\times3^2\times5\times11^2)
Why is this the correct answer?
Step 1: For a perfect cube, exponents should be multiples of 3. Step 2: Reduce 8 to 6, 5 to 3, 4 to 3, and 2 to 0 for the smallest divisor. Step 3: So the divisor is (2^2\times3^2\times5\times11^2).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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