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If the HCF of two numbers is (2^2\times3) and their LCM is (2^5\times3^3\times5), what is the prime factorised form of their product?
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Answer and explanation
Correct answer: (2^7\times3^4\times5)
Step 1: Product of two numbers equals HCF multiplied by LCM. Step 2: Multiply (2^2\times3) with (2^5\times3^3\times5); add exponents to get (2^7\times3^4\times5). Step 3: When multiplying same bases, add exponents.
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What is the correct answer to this question?
(2^7\times3^4\times5)
Why is this the correct answer?
Step 1: Product of two numbers equals HCF multiplied by LCM. Step 2: Multiply (2^2\times3) with (2^5\times3^3\times5); add exponents to get (2^7\times3^4\times5). Step 3: When multiplying same bases, add exponents.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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