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If the graph of (p(x)=x^2+px+q) cuts the (x)-axis at ((-2,0)) and ((5,0)), what will be the values of (p) and (q)?

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Answer and explanation

Correct answer: (p=-3, q=-10)

The zeroes are (-2) and (5), so the polynomial is ((x+2)(x-5)=x^2-3x-10). Tip: form factors from graph intersections.

Related tags

Zeroes To PolynomialCoefficientsGraph

Frequently asked questions

What is the correct answer to this question?

(p=-3, q=-10)

Why is this the correct answer?

The zeroes are (-2) and (5), so the polynomial is ((x+2)(x-5)=x^2-3x-10). Tip: form factors from graph intersections.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Geometrical meaning of the zeroes of a polynomial..

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