If (p(x)=x^2+dx+d^2) and (d\neq0), why will the graph not cut the (x)-axis?
Answer and explanation
Correct answer: Because its discriminant is negative
The discriminant is (d^2-4d^2=-3d^2<0), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.
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What is the correct answer to this question?
Because its discriminant is negative
Why is this the correct answer?
The discriminant is (d^2-4d^2=-3d^2<0), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Geometrical meaning of the zeroes of a polynomial..
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