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If (p(x)=x^2+cx+c^2) and (c\neq0), why will the graph not cut the (x)-axis?

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Answer and explanation

Correct answer: Because its discriminant is negative

The discriminant is (c^2-4c^2=-3c^2<0), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.

Related tags

DiscriminantNo Real ZeroGraph

Frequently asked questions

What is the correct answer to this question?

Because its discriminant is negative

Why is this the correct answer?

The discriminant is (c^2-4c^2=-3c^2<0), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Geometrical meaning of the zeroes of a polynomial..

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