If (p(x)=x^2+cx+c^2) and (c\neq0), why will the graph not cut the (x)-axis?
Answer and explanation
Correct answer: Because its discriminant is negative
The discriminant is (c^2-4c^2=-3c^2<0), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.
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What is the correct answer to this question?
Because its discriminant is negative
Why is this the correct answer?
The discriminant is (c^2-4c^2=-3c^2<0), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Geometrical meaning of the zeroes of a polynomial..
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