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If n(A)=4x+5, n(B)=3x+8, n(A∩B)=2x+1, and n(A∪B)=72, what is the value of x?

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Answer and explanation

Correct answer: 12

The governing Venn-diagram relation is n(A ∪ B) = n(A) + n(B) − n(A ∩ B), since the common region is counted twice in the first two terms. Substitution gives 72 = (4x+5) + (3x+8) − (2x+1). Simplifying, 72 = 5x + 12, so 5x = 60 and x = 12. The values then give valid nonnegative region counts, confirming the result. Hence option A is uniquely correct.

Tags

setsVenn diagramsunionintersectioncardinalityMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

12

Why is this the correct answer?

The governing Venn-diagram relation is n(A ∪ B) = n(A) + n(B) − n(A ∩ B), since the common region is counted twice in the first two terms. Substitution gives 72 = (4x+5) + (3x+8) − (2x+1). Simplifying, 72 = 5x + 12, so 5x = 60 and x = 12. The values then give valid nonnegative region counts, confirming the result. Hence option A is uniquely correct.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Venn Diagrams.

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