If (n=2^8\times3^3\times5^5), by which number must (n) be divisible?
Advertisement
Answer and explanation
Correct answer: (2^7\times3^2\times5^4)
Step 1: For divisibility, each exponent in the divisor must be less than or equal to the corresponding exponent in the number. Step 2: (2^7), (3^2), and (5^4) are all available in (n). Step 3: Therefore, (n) must be divisible by (2^7\times3^2\times5^4).
Frequently asked questions
What is the correct answer to this question?
(2^7\times3^2\times5^4)
Why is this the correct answer?
Step 1: For divisibility, each exponent in the divisor must be less than or equal to the corresponding exponent in the number. Step 2: (2^7), (3^2), and (5^4) are all available in (n). Step 3: Therefore, (n) must be divisible by (2^7\times3^2\times5^4).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
Advertisement