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If (N=2^3\times3^2\times5), what is the total number of positive factors of (N)?
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Answer and explanation
Correct answer: (24)
Step 1: For prime factorisation (p^a q^b r^c), total factors are ((a+1)(b+1)(c+1)). Step 2: Here the powers are (3,2,1), so factors (=(4)(3)(2)=24). Step 3: In exams, always add (1) to each exponent before multiplying.
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What is the correct answer to this question?
(24)
Why is this the correct answer?
Step 1: For prime factorisation (p^a q^b r^c), total factors are ((a+1)(b+1)(c+1)). Step 2: Here the powers are (3,2,1), so factors (=(4)(3)(2)=24). Step 3: In exams, always add (1) to each exponent before multiplying.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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