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If (k=2^3\times3^2\times5^2\times7), how many factors of (k) are divisible by (15)?

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Answer and explanation

Correct answer: (32)

Step 1: Since (15=3\times5), the factor must contain both (3) and (5). Step 2: Power choices are (2:4) choices, (3:2) choices, (5:2) choices, and (7:2) choices. Total (=4\times2\times2\times2=32). Step 3: Start restricted prime powers from the minimum required value.

Related tags

Real NumbersFactor CountingDivisible By 15Prime Factorisation

Frequently asked questions

What is the correct answer to this question?

(32)

Why is this the correct answer?

Step 1: Since (15=3\times5), the factor must contain both (3) and (5). Step 2: Power choices are (2:4) choices, (3:2) choices, (5:2) choices, and (7:2) choices. Total (=4\times2\times2\times2=32). Step 3: Start restricted prime powers from the minimum required value.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.

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