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If both (p) and (q) are found even in the proof of (\sqrt{2}), which statement does it refute?
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Answer and explanation
Correct answer: (\gcd(p,q)=1)
Step 1: If both are even, both (p) and (q) are divisible by (2). Step 2: Then their greatest common divisor cannot remain (1). Step 3: Therefore the condition (\gcd(p,q)=1) is refuted.
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What is the correct answer to this question?
(\gcd(p,q)=1)
Why is this the correct answer?
Step 1: If both are even, both (p) and (q) are divisible by (2). Step 2: Then their greatest common divisor cannot remain (1). Step 3: Therefore the condition (\gcd(p,q)=1) is refuted.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.
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