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If A = {x ∈ N : x ≤ 20}, B = {x : x is odd and x ≤ 20}, and C = {x : x is a multiple of 5 and x ≤ 20}, what is n(B ∩ C)?

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Answer and explanation

Correct answer: 2

The positive multiples of 5 not exceeding 20 are 5, 10, 15, and 20. Of these, 5 and 15 are odd, whereas 10 and 20 are even. Therefore B ∩ C = {5, 15}, and its cardinality is 2. Set A gives the common upper bound but is not needed for this particular intersection.

Tags

setsset-builder-notationintersectionodd-numbersVenn DiagramsMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

2

Why is this the correct answer?

The positive multiples of 5 not exceeding 20 are 5, 10, 15, and 20. Of these, 5 and 15 are odd, whereas 10 and 20 are even. Therefore B ∩ C = {5, 15}, and its cardinality is 2. Set A gives the common upper bound but is not needed for this particular intersection.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Venn Diagrams.

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