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Class 10MathematicsQuadratic EquationsWord Problems and ApplicationsEasyLevel 42
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If a rectangle has breadth (x) and length (x+10) and area (651), which equation is correct?

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Answer and explanation

Correct answer: (x(x+10)=651)

Area of a rectangle is length (\times) breadth, so (x(x+10)=651) is correct. Identifying the formula is the first step.

Related tags

Quadratic EquationsEquation FormationRectangle

Frequently asked questions

What is the correct answer to this question?

(x(x+10)=651)

Why is this the correct answer?

Area of a rectangle is length (\times) breadth, so (x(x+10)=651) is correct. Identifying the formula is the first step.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.

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  1. 1The square of a number is 6 more than 5 times the number. If the number is x, what is the equation?
  2. 2The product of two consecutive positive integers is (72). What is the smaller integer?
  3. 3The product of two consecutive positive integers is (132). What is the larger integer?
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  5. 5A rectangle has breadth (6) m and area (96) square m. If its length is (x) m, which equation is correct?
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  8. 8A number multiplied by its next integer gives (56). What is the number?
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