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If a quadratic polynomial has real zeroes 1 and 4, at which points will its graph cut the x-axis?

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Answer and explanation

Correct answer: (1, 0) and (4, 0)

If a polynomial has a zero a, its graph meets the x-axis at (a,0) because the y-value is zero there. So zeros 1 and 4 give intersection points (1,0) and (4,0). Option B is wrong because those are points on the y-axis, C is wrong since y≠0 at those coordinates, and D is wrong because the signs of the zeros are incorrect. Exam tip: Always convert a zero a to the point (a,0) on the graph.

Related tags

PolynomialsZerosGraphsX-AxisQuadratic

Frequently asked questions

What is the correct answer to this question?

(1, 0) and (4, 0)

Why is this the correct answer?

If a polynomial has a zero a, its graph meets the x-axis at (a,0) because the y-value is zero there. So zeros 1 and 4 give intersection points (1,0) and (4,0). Option B is wrong because those are points on the y-axis, C is wrong since y≠0 at those coordinates, and D is wrong because the signs of the zeros are incorrect. Exam tip: Always convert a zero a to the point (a,0) on the graph.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Geometrical meaning of the zeroes of a polynomial..

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