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Class 10MathematicsReal NumbersEuclid’s Division LemmaHard
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If a number leaves remainder 5 when divided by 27, what is the remainder when 8 times the number is divided by 27?

Answer and explanation

Correct answer: 13

Step 1: For eight times the number, the remainder part is (8\times5=40). Step 2: (40=27+13), so the final remainder is 13. Step 3: After multiplication, reduce the result below the divisor.

Related tags

Euclids-Division-LemmaMultiple-RemainderHardEuclid’s Division LemmaEuclid S Division LemmaReal NumbersMathematicsClass 10 Mcq
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10 more MCQs
  1. 1In Euclid’s Division Lemma, if (a) and (b) are positive integers, which condition is correct for the remainder (r)?
  2. 2If (35=6q+r) and (0 \le r < 6), what are the values of (q) and (r)?
  3. 3Which is the standard form of Euclid’s Division Lemma?
  4. 4If a number leaves remainder (0) when divided by (9), in which form can it be written?
  5. 5What possible remainders can occur when an integer is divided by (5)?
  6. 6What is the remainder when (52) is divided by (7)?
  7. 7Which condition is necessary for (b) in Euclid’s Division Lemma?
  8. 8If (a=17) and (b=4), which is the correct Euclidean form (a=bq+r)?
  9. 9How many possible remainders are there when a number is divided by (3)?
  10. 10If a number is odd, what remainder will it leave when divided by (2)?
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