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If (A=2^3\times3^5) and (B=2^5\times3^2), how many factors does the HCF of (A) and (B) have?
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Answer and explanation
Correct answer: (12)
Step 1: HCF uses the smaller exponents. Step 2: HCF (=2^3\times3^2). Its number of factors is ((3+1)(2+1)=12). Step 3: First find the HCF, then count its factors.
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What is the correct answer to this question?
(12)
Why is this the correct answer?
Step 1: HCF uses the smaller exponents. Step 2: HCF (=2^3\times3^2). Its number of factors is ((3+1)(2+1)=12). Step 3: First find the HCF, then count its factors.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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