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If (360=2^3\times3^2\times5), how many factors of (360) are odd?
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Answer and explanation
Correct answer: (6)
Step 1: An odd factor must not contain the prime (2). Step 2: Power of (2) is only (0); power of (3) has (3) choices and power of (5) has (2) choices. Total (=3\times2=6). Step 3: When counting odd factors, ignore the power choices of (2) except zero.
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What is the correct answer to this question?
(6)
Why is this the correct answer?
Step 1: An odd factor must not contain the prime (2). Step 2: Power of (2) is only (0); power of (3) has (3) choices and power of (5) has (2) choices. Total (=3\times2=6). Step 3: When counting odd factors, ignore the power choices of (2) except zero.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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