An item sold at ₹x gives total revenue x(50 − x). If the total revenue is 600, what is the larger value of x?

Correct answer: 30

Set the stated revenue equal to 600: x(50 − x) = 600. Expanding and rearranging gives 50x − x² = 600, so x² − 50x + 600 = 0. The quadratic factors as (x − 20)(x − 30) = 0. Therefore the two possible values are x = 20 and x = 30, and the larger one is 30. Both can be verified in the original model: 20(50 − 20) = 20 × 30 = 600, while 30(50 − 30) = 30 × 20 = 600. Hence option A is correct. Option B is the smaller valid value, option C gives revenue 625, and option D gives revenue 400. The wording asks specifically for the larger solution.