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A wire is bent into a square whose area is 625 square centimetres. What is the length of the wire?

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Answer and explanation

Correct answer: 100 cm

Use the governing square formulas: area = side² and perimeter = 4 × side. Let the side of the square be s centimetres. The given area gives s² = 625, so the positive side length is s = 25 cm. Because the wire is bent around the whole square, its length is the complete perimeter, not just one side. Thus wire length = 4s = 4 × 25 = 100 cm. Option C is correct. The value 25 cm would be the length of one side, so it is not an option for the total wire. Values 80 cm and 90 cm do not equal the required perimeter, and 125 cm is also inconsistent with a square having area 625 square centimetres.

Related tags

Quadratic-EquationsSquarePerimeter-And-AreaWord Problems And ApplicationsQuadratic EquationsMathematicsClass 10 Mcq

Frequently asked questions

What is the correct answer to this question?

100 cm

Why is this the correct answer?

Use the governing square formulas: area = side² and perimeter = 4 × side. Let the side of the square be s centimetres. The given area gives s² = 625, so the positive side length is s = 25 cm. Because the wire is bent around the whole square, its length is the complete perimeter, not just one side. Thus wire length = 4s = 4 × 25 = 100 cm. Option C is correct. The value 25 cm would be the length of one side, so it is not an option for the total wire. Values 80 cm and 90 cm do not equal the required perimeter, and 125 cm is also inconsistent with a square having area 625 square centimetres.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.

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