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A son's present age is \(x\) years, and his mother's present age is 20 years more than his. Five years ago, the product of their ages was 189. What is the son's present age?

Answer and explanation

Correct answer: 12 years

The mother's present age is \(x+20\) years. Five years ago, their ages were \(x-5\) and \(x+15\) years, respectively. Thus, \((x-5)(x+15)=189\), which gives \(x^2+10x-264=0\). Factoring, \((x-12)(x+22)=0\). Since age cannot be negative, \(x=12\) years, so option C is correct. In age problems, remember to subtract the stated number of years from both present ages.

Related tags

Quadratic EquationsAge ProblemsWord ProblemsAlgebraic EquationsWord Problems And ApplicationsMathematicsClass 10 Mcq

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