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A poster has an area of \(216\) square units. Its length is \(6\) units more than its breadth. What is the breadth of the poster?

Answer and explanation

Correct answer: 12

Let the breadth be \(x\) units. Then the length is \(x+6\) units, so \(x(x+6)=216\), or \(x^2+6x-216=0\). Factoring gives \((x-12)(x+18)=0\), so \(x=12\) or \(x=-18\). Since a length cannot be negative, the breadth is \(12\) units. Option 18 is the length, not the breadth. Exam tip: In rectangle-area problems, let one side be \(x\) and express the other side in terms of \(x\) before forming the quadratic equation.

Related tags

Quadratic-EquationsWord-ProblemsArea-Of-RectangleWord Problems And ApplicationsQuadratic EquationsMathematicsClass 10 Mcq

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