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Subjects
Class 10MathematicsQuadratic EquationsWord Problems and ApplicationsExpertLevel 41
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A person travels (150\text{ km}) by car. On return, the speed is (25\text{ km/h}) less and the time is (1\text{ h}) more. What was the onward speed?

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Answer and explanation

Correct answer: (75\text{ km/h})

Let the onward speed be (x), then (\frac{150}{x-25}-\frac{150}{x}=1). This gives (x^2-25x-3750=0), so (x=75).

Related tags

Quadratic EquationsSpeed Time DistanceReturn Journey

Frequently asked questions

What is the correct answer to this question?

(75\text{ km/h})

Why is this the correct answer?

Let the onward speed be (x), then (\frac{150}{x-25}-\frac{150}{x}=1). This gives (x^2-25x-3750=0), so (x=75).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.

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