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A ladder reaches (96) m up a wall. The ladder length is (32) m more than the distance of its foot from the wall. What is that distance?

Answer and explanation

Correct answer: (128) m

The direct answer is B, 128 m. Let the ground distance be x metres. The height is 96 m and the ladder length is x+32 m, the hypotenuse. Thus \\(x^2+96^2=(x+32)^2\\). Expanding gives \\(x^2+9216=x^2+64x+1024\\), so \\(64x=8192\\) and x=128. Option B is correct; the ladder is 160 m long. Option A, 112, would give a ladder of 144 and does not satisfy Pythagoras. Option C, 144, would give a ladder of 176 and also fails. Option D, 160, is the resulting ladder length, not the base distance; using it as x would make the ladder 192. Remember to assign the hypotenuse as x plus the stated extra length.

Related tags

Quadratic EquationsLadderApplication

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