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If A = 1.2, B = −3.8, and C = 4.2 on the number line, how much greater is distance AB than distance AC?

Answer and explanation

Correct answer: 2

The governing concept is that the distance between two points on a number line is the absolute value of the difference of their coordinates. Therefore AB=|1.2−(−3.8)|=|5.0|=5 units. Similarly, AC=|1.2−4.2|=|−3.0|=3 units. The question asks how much greater AB is than AC, so subtract the two distances: 5−3=2 units. Hence option A is correct. Absolute value is essential because distance cannot be negative, even when a directed difference is negative. Option B does not equal the difference of the calculated distances, while options C and D are not supported by the coordinate calculation.

Related tags

Number-LineDistanceAbsolute-ValueReal-NumbersRepresenting Real Numbers On The Number LinePolynomialsMathematicsClass 10 Mcq

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