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projectile MCQ Questions for Class 10

projectile se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

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Question 1/3 Expert Mathematics Quadratic Equations 5. Word Problems and Applications Class 10 Level 42

एक गेंद की ऊँचाई \(h=30t-5t^2\) मीटर है। वह जमीन पर वापस कब आएगी?

The height of a ball is \(h=30t-5t^2\) m. When will it return to the ground?

Explanation opens after your attempt
Correct Answer

C. (6) सेकंड(6) s

Step 1

Concept

On the ground, (h=0). From \(30t-5t^2=0\), (t=0) or (t=6), so the return time is (6) seconds.

Step 2

Why this answer is correct

The correct answer is C. (6) सेकंड / (6) s. On the ground, (h=0). From \(30t-5t^2=0\), (t=0) or (t=6), so the return time is (6) seconds.

Step 3

Exam Tip

जमीन पर (h=0) होगा। \(30t-5t^2=0\) से (t=0) या (t=6) मिलता है इसलिए वापसी समय (6) सेकंड है।

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Question 2/3 Expert Mathematics Quadratic Equations 5. Word Problems and Applications Class 10 Level 42

एक वस्तु को ऊपर फेंका गया और उसकी ऊँचाई \(h=20t-5t^2\) मीटर है। वस्तु (15) मीटर की ऊँचाई पर कब होगी?

An object is thrown upward and its height is \(h=20t-5t^2\) m. When will it be at a height of (15) m?

Explanation opens after your attempt
Correct Answer

A. (1) सेकंड और (3) सेकंड(1) s and (3) s

Step 1

Concept

From \(20t-5t^2=15\), we get \(t^2-4t+3=0\). Hence (t=1) and (t=3) seconds.

Step 2

Why this answer is correct

The correct answer is A. (1) सेकंड और (3) सेकंड / (1) s and (3) s. From \(20t-5t^2=15\), we get \(t^2-4t+3=0\). Hence (t=1) and (t=3) seconds.

Step 3

Exam Tip

\(20t-5t^2=15\) से \(t^2-4t+3=0\) बनता है। अतः (t=1) और (t=3) सेकंड हैं।

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Question 3/3 Expert Mathematics Quadratic Equations 5. Word Problems and Applications Class 10 Level 41

एक गेंद को (20 m/s) की चाल से ऊपर फेंका गया। उसकी ऊँचाई \(h=20t-5t^2\) है। गेंद (15 m) ऊँचाई पर किस समय होगी?

A ball is thrown upward with speed (20 m/s\(). Its height is (h=20t-5t^2). At what times will it be at height (15\) m)?

Explanation opens after your attempt
Correct Answer

A. (1 s) और (3 s)(1 s) and (3 s)

Step 1

Concept

From \(20t-5t^2=15\), we get \(t^2-4t+3=0\). Hence (t=1) and (t=3), representing upward and downward motion.

Step 2

Why this answer is correct

The correct answer is A. (1 s) और (3 s) / (1 s) and (3 s\(). From (20t-5t^2=15), we get (t^2-4t+3=0). Hence (t=1) and (t=3), representing upward and downward motion.\)

Step 3

Exam Tip

\(20t-5t^2=15\) से \(t^2-4t+3=0\)। इसलिए (t=1) और (t=3), जो ऊपर जाते और नीचे आते समय हैं।

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