यदि total population का 36 प्रतिशत total area के 12 प्रतिशत में और बाकी population शेष area में रहती है, तो first portion remaining portion से कितनी गुना dense है?
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B. 4.125 गुना4.125 times
Simple Explanation
First portion की relative density \(0.36/0.12=3\) है। Remaining portion में 64 percent population 88 percent area में है, इसलिए relative density \(0.64/0.88=0.72727...\) है। Ratio \(3/0.72727...\approx4.125\) है। इसलिए दूसरा विकल्प सही है। यहां regional average से नहीं बल्कि remaining portion से comparison पूछा गया है। / The first portion has relative density \(0.36/0.12=3\). The remainder contains 64 percent of the population in 88 percent of the area, giving relative density \(0.64/0.88=0.72727...\). Their ratio is \(3/0.72727...\approx4.125\). Therefore, the second option is correct. The comparison is with the remaining portion, not with the regional average.
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