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19 results found for "defective item" in Class 10.

Question Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वस्तु पर (1200) रुपये खर्च होते हैं। यदि प्रति वस्तु मूल्य (10) रुपये कम हो जाए तो उसी धन से (4) वस्तुएँ अधिक मिलती हैं। मूल प्रति वस्तु मूल्य क्या था?

A total of (1200) rupees is spent on some items. If the price per item decreases by (10) rupees, (4) more items can be bought for the same money. What was the original price per item?

Explanation opens after your attempt
Correct Answer

B. (60) रुपये(60) rupees

Step 1

Concept

If original price is (x), then \(\frac{1200}{x-10}-\frac{1200}{x}=4\). Solving gives (x=60).

Step 2

Why this answer is correct

The correct answer is B. (60) रुपये / (60) rupees. If original price is (x), then \(\frac{1200}{x-10}-\frac{1200}{x}=4\). Solving gives (x=60).

Step 3

Exam Tip

मूल मूल्य (x) हो तो \(\frac{1200}{x-10}-\frac{1200}{x}=4\)। हल करने पर (x=60) मिलता है।

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Question Easy General Knowledge Indian History Important Revolts and Movements Class 10 Level 29

धरासना सत्याग्रह में किस वस्तु से जुड़े सरकारी स्थल को निशाना बनाया गया था?

In Dharasana Satyagraha the government site related to which item was targeted?

Explanation opens after your attempt
Correct Answer

A. नमकSalt

Step 1

Concept

Dharasana Satyagraha was linked with salt works and protest against Salt Law. Exam tip: remember events after Dandi.

Step 2

Why this answer is correct

The correct answer is A. नमक / Salt. Dharasana Satyagraha was linked with salt works and protest against Salt Law. Exam tip: remember events after Dandi.

Step 3

Exam Tip

धरासना सत्याग्रह नमक कारखाने और नमक कानून विरोध से जुड़ा था। परीक्षा में डांडी के बाद की घटनाएं याद रखें।

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Question Easy General Knowledge Indian History Indian Freedom Movement Class 10 Level 24

दांडी मार्च में गांधीजी ने किस वस्तु को आंदोलन का प्रतीक बनाया?

In the Dandi March which item did Gandhi make a symbol of the movement?

Explanation opens after your attempt
Correct Answer

C. नमकSalt

Step 1

Concept

Gandhi made salt a symbol connected with common life. Exam tip is to remember salt law and Dandi.

Step 2

Why this answer is correct

The correct answer is C. नमक / Salt. Gandhi made salt a symbol connected with common life. Exam tip is to remember salt law and Dandi.

Step 3

Exam Tip

गांधीजी ने नमक को जनजीवन से जुड़ा प्रतीक बनाया। परीक्षा में नमक कानून और दांडी याद रखें।

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Question Medium General Knowledge Indian History Medieval Indian History Class 10 Level 14

गोलकुंडा मध्यकाल में किस वस्तु के व्यापार के लिए प्रसिद्ध था?

Golconda was famous in the medieval period for the trade of which item?

Explanation opens after your attempt
Correct Answer

A. हीरेDiamonds

Step 1

Concept

Golconda was famous for the trade of diamonds and precious stones. Trade goods are important in economic history.

Step 2

Why this answer is correct

The correct answer is A. हीरे / Diamonds. Golconda was famous for the trade of diamonds and precious stones. Trade goods are important in economic history.

Step 3

Exam Tip

गोलकुंडा हीरे और कीमती पत्थरों के व्यापार के लिए प्रसिद्ध था। आर्थिक इतिहास में व्यापारिक वस्तुएं महत्वपूर्ण हैं।

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Question Expert General Knowledge Indian History Ancient Indian History Class 10 Level 8

अरिकामेडु में एंफोरा अवशेष किस आयात वस्तु से अधिक जुड़े माने जाते हैं?

Amphora remains at Arikamedu are generally linked with which imported item?

Explanation opens after your attempt
Correct Answer

A. रोमन शराब या तेल के कंटेनरContainers for Roman wine or oil

Step 1

Concept

Amphorae are archaeological clues of foreign Mediterranean trade. For exams, connect Arikamedu with Indo-Roman trade.

Step 2

Why this answer is correct

The correct answer is A. रोमन शराब या तेल के कंटेनर / Containers for Roman wine or oil. Amphorae are archaeological clues of foreign Mediterranean trade. For exams, connect Arikamedu with Indo-Roman trade.

Step 3

Exam Tip

एंफोरा विदेशी भूमध्यसागरीय व्यापार का पुरातात्त्विक संकेत है। परीक्षा में अरिकामेडु को भारत रोम व्यापार से जोड़ें।

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Question Hard General Knowledge Indian History Ancient Indian History Class 10 Level 8

अर्थशास्त्र में सुराध्यक्ष किस वस्तु के नियंत्रण से संबंधित अधिकारी था?

In Arthashastra, Suradhyaksha was an officer related to control of which item?

Explanation opens after your attempt
Correct Answer

A. मदिराLiquor

Step 1

Concept

Suradhyaksha is considered an officer related to liquor production and control. For exams, understand Mauryan economic regulation.

Step 2

Why this answer is correct

The correct answer is A. मदिरा / Liquor. Suradhyaksha is considered an officer related to liquor production and control. For exams, understand Mauryan economic regulation.

Step 3

Exam Tip

सुराध्यक्ष मदिरा उत्पादन और नियंत्रण से जुड़ा अधिकारी माना जाता है। परीक्षा में आर्थिक नियंत्रण की मौर्य व्यवस्था समझें।

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Question Hard General Knowledge Indian History Ancient Indian History Class 10 Level 6

चेरों के मुज़िरिस बंदरगाह पर रोमन व्यापार किस वस्तु से विशेष रूप से जुड़ा था?

Roman trade at the Chera port Muziris was especially linked with which item?

Explanation opens after your attempt
Correct Answer

A. काली मिर्च और मसालेPepper and spices

Step 1

Concept

Muziris was famous for spices and foreign trade. For exams, connect the Cheras with west coast trade.

Step 2

Why this answer is correct

The correct answer is A. काली मिर्च और मसाले / Pepper and spices. Muziris was famous for spices and foreign trade. For exams, connect the Cheras with west coast trade.

Step 3

Exam Tip

मुज़िरिस मसाले और विदेशी व्यापार के लिए प्रसिद्ध था। परीक्षा में चेरों को पश्चिमी तट व्यापार से जोड़ें।

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Question Medium General Knowledge Indian History Ancient Indian History Class 10 Level 7

पांड्य क्षेत्र का कोरकई बंदरगाह किस वस्तु के व्यापार के लिए प्रसिद्ध था?

The Korkai port of the Pandya region was famous for trade in which item?

Explanation opens after your attempt
Correct Answer

D. मोतीPearls

Step 1

Concept

Korkai was a famous pearl trade centre of the Pandya region. For exams, connect the Pandyas with Madurai and pearl trade.

Step 2

Why this answer is correct

The correct answer is D. मोती / Pearls. Korkai was a famous pearl trade centre of the Pandya region. For exams, connect the Pandyas with Madurai and pearl trade.

Step 3

Exam Tip

कोरकई पांड्य क्षेत्र का प्रसिद्ध मोती व्यापार केंद्र था। परीक्षा में पांड्यों को मदुरै और मोती व्यापार से जोड़ें।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

एक दुकान में दो वस्तुओं की कुल कीमत (154) है और पहली वस्तु दूसरी से (22) महंगी है। ग्राफीय समाधान कौन सा है?

In a shop, the total cost of two items is (154), and the first item is (22) costlier than the second. What is the graphical solution?

Explanation opens after your attempt
Correct Answer

A. ((88,66))

Step 1

Concept

The equations are (x+y=154) and (x-y=22). Solving gives (x=88), (y=66), which is the graph intersection.

Step 2

Why this answer is correct

The correct answer is A. ((88,66)). The equations are (x+y=154) and (x-y=22). Solving gives (x=88), (y=66), which is the graph intersection.

Step 3

Exam Tip

समीकरण (x+y=154) और (x-y=22) हैं। इन्हें हल करने पर (x=88), (y=66), जो ग्राफ का प्रतिच्छेद है।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

एक दुकान में दो वस्तुओं की कुल कीमत (126) है और पहली वस्तु दूसरी से (18) महंगी है। ग्राफीय समाधान कौन सा है?

In a shop, the total cost of two items is (126), and the first item is (18) costlier than the second. What is the graphical solution?

Explanation opens after your attempt
Correct Answer

A. ((72,54))

Step 1

Concept

The equations are (x+y=126) and (x-y=18). Solving gives (x=72), (y=54), which is the graph intersection.

Step 2

Why this answer is correct

The correct answer is A. ((72,54)). The equations are (x+y=126) and (x-y=18). Solving gives (x=72), (y=54), which is the graph intersection.

Step 3

Exam Tip

समीकरण (x+y=126) और (x-y=18) हैं। इन्हें हल करने पर (x=72), (y=54), जो ग्राफ का प्रतिच्छेद है।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

एक दुकान में दो वस्तुओं की कुल कीमत (90) है और पहली वस्तु दूसरी से (14) महंगी है। ग्राफीय समाधान कौन सा है?

In a shop, the total cost of two items is (90), and the first item is (14) costlier than the second. What is the graphical solution?

Explanation opens after your attempt
Correct Answer

A. ((52,38))

Step 1

Concept

The equations are (x+y=90) and (x-y=14). Solving gives (x=52), (y=38), which is the graph intersection.

Step 2

Why this answer is correct

The correct answer is A. ((52,38)). The equations are (x+y=90) and (x-y=14). Solving gives (x=52), (y=38), which is the graph intersection.

Step 3

Exam Tip

समीकरण (x+y=90) और (x-y=14) हैं। इन्हें हल करने पर (x=52), (y=38), जो ग्राफ का प्रतिच्छेद है।

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Question Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक दुकानदार ने (x) वस्तुएँ (720) रुपये में खरीदीं। यदि (3) वस्तुएँ अधिक मिलतीं तो प्रति वस्तु लागत (40) रुपये कम होती। (x) क्या है?

A shopkeeper bought (x) items for (720) rupees. If he had received (3) more items, the cost per item would be (40) rupees less. What is (x)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

We get \(\frac{720}{x}-\frac{720}{x+3}=40\). This gives \(40x^2+120x-2160=0\), so (x=6).

Step 2

Why this answer is correct

The correct answer is A. (6). We get \(\frac{720}{x}-\frac{720}{x+3}=40\). This gives \(40x^2+120x-2160=0\), so (x=6).

Step 3

Exam Tip

\(\frac{720}{x}-\frac{720}{x+3}=40\) बनता है। इससे \(40x^2+120x-2160=0\) और (x=6) मिलता है।

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Question Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक दुकानदार (x) रुपये प्रति वस्तु के हिसाब से (80-x) वस्तुएँ बेचता है। कुल आय (1500) है। (x) का छोटा मान क्या है?

A shopkeeper sells (80-x) items at (x) rupees per item. The total revenue is (1500). What is the smaller value of (x)?

Explanation opens after your attempt
Correct Answer

A. (30)

Step 1

Concept

The equation is (x(80-x)=1500). From \(x^2-80x+1500=0\), (x=30) or (50), so the smaller value is (30).

Step 2

Why this answer is correct

The correct answer is A. (30). The equation is (x(80-x)=1500). From \(x^2-80x+1500=0\), (x=30) or (50), so the smaller value is (30).

Step 3

Exam Tip

समीकरण (x(80-x)=1500) है। \(x^2-80x+1500=0\) से (x=30) या (50), छोटा मान (30) है।

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Question Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक वस्तु को (x) रुपये में बेचने पर कुल आय (x(70-x)) है। यदि कुल आय (1200) है, तो (x) का बड़ा मान क्या है?

An item sold at (x) rupees gives total revenue (x(70-x)). If the total revenue is (1200), what is the larger value of (x)?

Explanation opens after your attempt
Correct Answer

A. (40)

Step 1

Concept

The equation is (x(70-x)=1200). This gives (x=30) or (40); the larger value is (40).

Step 2

Why this answer is correct

The correct answer is A. (40). The equation is (x(70-x)=1200). This gives (x=30) or (40); the larger value is (40).

Step 3

Exam Tip

समीकरण (x(70-x)=1200) है। इससे (x=30) या (40); बड़ा मान (40) है।

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Question Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक दुकानदार (x) रुपये प्रति वस्तु के हिसाब से (60-x) वस्तुएँ बेचता है। कुल आय (875) है। (x) का छोटा मान क्या है?

A shopkeeper sells (60-x) items at (x) rupees per item. The total revenue is (875). What is the smaller value of (x)?

Explanation opens after your attempt
Correct Answer

A. (25)

Step 1

Concept

The equation is (x(60-x)=875). From \(x^2-60x+875=0\), (x=25) or (35), so the smaller value is (25).

Step 2

Why this answer is correct

The correct answer is A. (25). The equation is (x(60-x)=875). From \(x^2-60x+875=0\), (x=25) or (35), so the smaller value is (25).

Step 3

Exam Tip

समीकरण (x(60-x)=875) है। \(x^2-60x+875=0\) से (x=25) या (35), छोटा मान (25) है।

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Question Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक वस्तु को (₹x) में बेचने पर कुल आय (x(50-x)) है। यदि कुल आय (600) है, तो (x) का बड़ा मान क्या है?

An item sold at (₹x) gives total revenue (x(50-x)). If the total revenue is (600), what is the larger value of (x)?

Explanation opens after your attempt
Correct Answer

A. (30)

Step 1

Concept

The equation is (x(50-x)=600). This gives \(x^2-50x+600=0\), so (x=20) or (30); the larger value is (30).

Step 2

Why this answer is correct

The correct answer is A. (30). The equation is (x(50-x)=600). This gives \(x^2-50x+600=0\), so (x=20) or (30); the larger value is (30).

Step 3

Exam Tip

समीकरण (x(50-x)=600) है। इससे \(x^2-50x+600=0\), इसलिए (x=20) या (30); बड़ा मान (30) है।

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Question Medium Science Chemical Substances – Nature and Behaviour Chemical Reactions and Equations Class 10 Level 3

यदि किसी पैक खाद्य पदार्थ में तेल अधिक है तो उसे सुरक्षित रखने में कौन सा उपाय अधिक उचित है?

If a packed food item contains more oil which method is more suitable to preserve it?

Explanation opens after your attempt
Correct Answer

A. नाइट्रोजन भरकर वायुरुद्ध पैक करनाAirtight packing with nitrogen

Step 1

Concept

Oil can spoil by oxidation with oxygen.

Step 2

Why this answer is correct

Nitrogen and airtight packing reduce oxygen contact.

Step 3

Exam Tip

This reduces rancidity. चरण 1: तेल ऑक्सीजन से ऑक्सीकृत होकर खराब हो सकता है। चरण 2: नाइट्रोजन और वायुरुद्ध पैकिंग ऑक्सीजन संपर्क घटाते हैं। चरण 3: इससे विकृतगंधिता कम होती है।

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Question Hard General Knowledge Indian History Historical Monuments of India Class 10 Level 36

गोलकुंडा किला किस वस्तु के ऐतिहासिक व्यापार और खदान क्षेत्र से विशेष रूप से जुड़ा रहा है?

Golconda Fort was especially linked with the historical trade and mining region of which item?

Explanation opens after your attempt
Correct Answer

A. हीराDiamond

Step 1

Concept

The Golconda region was famous for diamond trade and mines. For exams remember forts along with their economic importance.

Step 2

Why this answer is correct

The correct answer is A. हीरा / Diamond. The Golconda region was famous for diamond trade and mines. For exams remember forts along with their economic importance.

Step 3

Exam Tip

गोलकुंडा क्षेत्र हीरों के व्यापार और खदानों के लिए प्रसिद्ध रहा। परीक्षा में किले और आर्थिक महत्व को साथ याद रखें।

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Question Hard Mathematics Real Numbers HCF and LCM using prime factorisation Class 10 Level 11

एक मैदान में (132) पौधे और (198) झंडे समान पंक्तियों में लगाने हैं। प्रत्येक पंक्ति में दोनों वस्तुओं की संख्या अलग-अलग समान रहे और पंक्तियों की संख्या अधिकतम हो। अधिकतम पंक्तियाँ कितनी होंगी?

In a ground, (132) plants and (198) flags are to be arranged in equal rows. Each row should have the same number of each item separately, and the number of rows should be maximum. What is the maximum number of rows?

Explanation opens after your attempt
Correct Answer

C. (66)

Step 1

Concept

The maximum number of rows is found by HCF.

Step 2

Why this answer is correct

\(132=2^2\times3\times11\) and \(198=2\times3^2\times11\), so HCF \(=2\times3\times11=66\).

Step 3

Exam Tip

For maximum equal arrangement, identify HCF. चरण 1: अधिकतम पंक्तियों की संख्या महत्तम समापवर्तक से मिलेगी। चरण 2: \(132=2^2\times3\times11\) और \(198=2\times3^2\times11\), इसलिए महत्तम समापवर्तक \(2\times3\times11=66\) है। चरण 3: अधिकतम समान व्यवस्था में महत्तम समापवर्तक पहचानें।

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