यदि \( \theta=38^\circ45' \) है तो उसका संपूरक कोण क्या है?
If \( \theta=38^\circ45' \), what is its complementary angle?
Explanation opens after your attempt
Correct Answer
A. \(51^\circ15'\)
Step 1
Concept
The complementary angle is \(90^\circ-38^\circ45'=51^\circ15'\). Treat \(90^\circ\) as \(89^\circ60'\) while subtracting.
Step 2
Why this answer is correct
The correct answer is A. \(51^\circ15'\). The complementary angle is \(90^\circ-38^\circ45'=51^\circ15'\). Treat \(90^\circ\) as \(89^\circ60'\) while subtracting.
Step 3
Exam Tip
संपूरक कोण \(90^\circ-38^\circ45'=51^\circ15'\) है। \(90^\circ\) को \(89^\circ60'\) मानकर घटाएं।
Mathematics Answer, Explanation and Revision Hints
यदि \( \theta=38^\circ45' \) है तो उसका संपूरक कोण क्या है? / If \( \theta=38^\circ45' \), what is its complementary angle?
Correct Answer: A. \(51^\circ15'\). Explanation: संपूरक कोण \(90^\circ-38^\circ45'=51^\circ15'\) है। \(90^\circ\) को \(89^\circ60'\) मानकर घटाएं। / The complementary angle is \(90^\circ-38^\circ45'=51^\circ15'\). Treat \(90^\circ\) as \(89^\circ60'\) while subtracting.
Which concept should I revise for this Mathematics MCQ?
The complementary angle is \(90^\circ-38^\circ45'=51^\circ15'\). Treat \(90^\circ\) as \(89^\circ60'\) while subtracting.
What exam hint can help solve this Mathematics question?
संपूरक कोण \(90^\circ-38^\circ45'=51^\circ15'\) है। \(90^\circ\) को \(89^\circ60'\) मानकर घटाएं।
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