यदि शुद्ध जल का हिमांक \(0^{\circ}C\) है और विलयन के लिए \(\Delta T_f = 1.5^{\circ}C\) है, तो विलयन का हिमांक क्या होगा?
If the freezing point of pure water is \(0^{\circ}C\) and \(\Delta T_f = 1.5^{\circ}C\), what is the freezing point of the solution?
Correct answer and explanation
B. \(-1.5^{\circ}C\)
Concept
हिमांक में कमी में ताप घटता है। / Freezing point depression means the temperature falls.
Why this answer is correct
\(0^{\circ}C - 1.5^{\circ}C = -1.5^{\circ}C\)। / \(0^{\circ}C - 1.5^{\circ}C = -1.5^{\circ}C\).
Exam Tip
अंतिम हिमांक निकालते समय \(\Delta T_f\) घटाएं। / Subtract \(\Delta T_f\) while finding final freezing point.
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