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Which term should be removed from (4x^2+7x-9) so that no constant term remains and two terms are left?(4x^2+7x-9) में से कौन-सा पद हटाने पर स्थिर पद नहीं रहेगा और दो पद बचेंगे?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -9-9
In \(4x^2+7x-9\), \(-9\) is the constant term because it has no \(x\). Removing \(-9\) leaves \(4x^2+7x\), which has exactly two terms and no constant term. If \(7x\) were removed, the constant term \(-9\) would still remain. Exam tip: A term without a variable is called a constant term.व्यंजक \(4x^2+7x-9\) में \(-9\) स्थिर पद है, क्योंकि इसमें \(x\) नहीं है। \(-9\) हटाने पर \(4x^2+7x\) बचता है, जिसमें ठीक दो पद हैं और कोई स्थिर पद नहीं है। \(7x\) हटाने पर \(-9\) स्थिर पद बना रहेगा। परीक्षा टिप: जिस पद में कोई चर न हो, वही स्थिर पद होता है।
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