Which is the general term of the geometric progression (64,32,16,8,\ldots)?
Answer and explanation
Correct answer: \(a_n=64\cdot\left(\frac{1}{2}\right)^{n-1}\)
The first term is (64) and the ratio is \(\frac{1}{2}\) so \(a_n=64\cdot\left(\frac{1}{2}\right)^{n-1}\). In exams use the fractional ratio in a decreasing sequence.
Frequently asked questions
What is the correct answer to this question?
\(a_n=64\cdot\left(\frac{1}{2}\right)^{n-1}\)
Why is this the correct answer?
The first term is (64) and the ratio is \(\frac{1}{2}\) so \(a_n=64\cdot\left(\frac{1}{2}\right)^{n-1}\). In exams use the fractional ratio in a decreasing sequence.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Geometric Progression.
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