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Which is the general term of the geometric progression (27,9,3,1,\ldots)?गुणोत्तर श्रेणी (27,9,3,1,\ldots) का सामान्य पद कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(a_n=27\cdot\left(\frac{1}{3}\right)^{n-1}\)\(a_n=27\cdot\left(\frac{1}{3}\right)^{n-1}\)
The first term is (27) and the ratio is \(\frac{1}{3}\), so \(a_n=27\cdot\left(\frac{1}{3}\right)^{n-1}\). In exams, use the fractional ratio in a decreasing sequence.पहला पद (27) और अनुपात \(\frac{1}{3}\) है, इसलिए \(a_n=27\cdot\left(\frac{1}{3}\right)^{n-1}\) है। परीक्षा में घटती श्रेणी में भिन्न अनुपात लगाएँ।
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