कौन-सा व्यंजक \(2x^2-3xy+y^2\) में \(-x^2+5xy-4y^2\) जोड़ने पर मिलता है?

Which expression is obtained by adding \(-x^2+5xy-4y^2\) to \(2x^2-3xy+y^2\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(x^2+2xy-3y^2\)

Step 1

Concept

Adding like terms gives \(2x^2-x^2=x^2\), (-3xy+5xy=2xy), and \(y^2-4y^2=-3y^2\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2+2xy-3y^2\). Adding like terms gives \(2x^2-x^2=x^2\), (-3xy+5xy=2xy), and \(y^2-4y^2=-3y^2\).

Step 3

Exam Tip

समान पद जोड़ने पर \(2x^2-x^2=x^2\), (-3xy+5xy=2xy), और \(y^2-4y^2=-3y^2\)।

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कौन-सा व्यंजक \(2x^2-3xy+y^2\) में \(-x^2+5xy-4y^2\) जोड़ने पर मिलता है? / Which expression is obtained by adding \(-x^2+5xy-4y^2\) to \(2x^2-3xy+y^2\)?

Correct Answer: A. \(x^2+2xy-3y^2\). Explanation: समान पद जोड़ने पर \(2x^2-x^2=x^2\), (-3xy+5xy=2xy), और \(y^2-4y^2=-3y^2\)। / Adding like terms gives \(2x^2-x^2=x^2\), (-3xy+5xy=2xy), and \(y^2-4y^2=-3y^2\).

Which concept should I revise for this Mathematics MCQ?

Adding like terms gives \(2x^2-x^2=x^2\), (-3xy+5xy=2xy), and \(y^2-4y^2=-3y^2\).

What exam hint can help solve this Mathematics question?

समान पद जोड़ने पर \(2x^2-x^2=x^2\), (-3xy+5xy=2xy), और \(y^2-4y^2=-3y^2\)।