कौन-सा व्यंजक \(2x^2-5x+3\) में \(x^2+4x-8\) जोड़ने पर मिलता है?

Which expression is obtained by adding \(x^2+4x-8\) to \(2x^2-5x+3\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(3x^2-x-5\)

Step 1

Concept

Add like terms: \(2x^2+x^2=3x^2\), (-5x+4x=-x), and (3-8=-5).

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-x-5\). Add like terms: \(2x^2+x^2=3x^2\), (-5x+4x=-x), and (3-8=-5).

Step 3

Exam Tip

समान पद जोड़ें: \(2x^2+x^2=3x^2\), (-5x+4x=-x), और (3-8=-5)।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा व्यंजक \(2x^2-5x+3\) में \(x^2+4x-8\) जोड़ने पर मिलता है? / Which expression is obtained by adding \(x^2+4x-8\) to \(2x^2-5x+3\)?

Correct Answer: A. \(3x^2-x-5\). Explanation: समान पद जोड़ें: \(2x^2+x^2=3x^2\), (-5x+4x=-x), और (3-8=-5)। / Add like terms: \(2x^2+x^2=3x^2\), (-5x+4x=-x), and (3-8=-5).

Which concept should I revise for this Mathematics MCQ?

Add like terms: \(2x^2+x^2=3x^2\), (-5x+4x=-x), and (3-8=-5).

What exam hint can help solve this Mathematics question?

समान पद जोड़ें: \(2x^2+x^2=3x^2\), (-5x+4x=-x), और (3-8=-5)।