गुणोत्तर श्रेणी \(4,12,36,\ldots\) के पहले (7) पदों का योग क्या है?
What is the sum of the first (7) terms of the geometric progression \(4,12,36,\ldots\)?
Explanation opens after your attempt
A. (4372)
Concept
(S_7=4\(3^7-1\)/(3-1)=4372). In exams first calculate the value of \(3^7\).
Why this answer is correct
The correct answer is A. (4372). (S_7=4\(3^7-1\)/(3-1)=4372). In exams first calculate the value of \(3^7\).
Exam Tip
(S_7=4\(3^7-1\)/(3-1)=4372) है। परीक्षा में पहले \(3^7\) का मान निकालें।
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