गुणोत्तर श्रेणी \(4,8,16,\ldots\) के पहले (10) पदों का योग क्या है?
What is the sum of the first (10) terms of the geometric progression \(4,8,16,\ldots\)?
Explanation opens after your attempt
A. (4092)
Concept
(S_{10}=4\(2^{10}-1\)=4092). In exams remembering \(2^{10}=1024\) is useful.
Why this answer is correct
The correct answer is A. (4092). (S_{10}=4\(2^{10}-1\)=4092). In exams remembering \(2^{10}=1024\) is useful.
Exam Tip
(S_{10}=4\(2^{10}-1\)=4092) है। परीक्षा में \(2^{10}=1024\) याद रखना उपयोगी है।
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