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What is the sum of four consecutive odd numbers starting from (n)?
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Answer and explanation
Correct answer: \(4n+12\)
If \(n\) is odd, the four consecutive odd numbers are \(n\), \(n+2\), \(n+4\), and \(n+6\). Their sum is \(n+(n+2)+(n+4)+(n+6)=4n+12\). \(4n+6\) is not the sum of all four terms. Exam tip: consecutive odd numbers differ by 2.
Frequently asked questions
What is the correct answer to this question?
\(4n+12\)
Why is this the correct answer?
If \(n\) is odd, the four consecutive odd numbers are \(n\), \(n+2\), \(n+4\), and \(n+6\). Their sum is \(n+(n+2)+(n+4)+(n+6)=4n+12\). \(4n+6\) is not the sum of all four terms. Exam tip: consecutive odd numbers differ by 2.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Algebraic expressions.
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