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What is the general term of the geometric progression (9,36,144,576,\ldots)?गुणोत्तर श्रेणी (9,36,144,576,\ldots) का सामान्य पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (a_n=9\cdot4^{n-1})(a_n=9\cdot4^{n-1})
The first term is (9) and the ratio is (4) so (a_n=9\cdot4^{n-1}). In exams match both the first term and the ratio.पहला पद (9) और अनुपात (4) है इसलिए (a_n=9\cdot4^{n-1}) है। परीक्षा में पहला पद और अनुपात दोनों मिलाएँ।
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