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What is the general term of the geometric progression (8,24,72,216,\ldots)?गुणोत्तर श्रेणी (8,24,72,216,\ldots) का सामान्य पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (a_n=8\cdot3^{n-1})(a_n=8\cdot3^{n-1})
The first term is (8) and the ratio is (3), so (a_n=8\cdot3^{n-1}). In exams, match both the first term and the ratio.पहला पद (8) और अनुपात (3) है, इसलिए (a_n=8\cdot3^{n-1}) है। परीक्षा में पहला पद और अनुपात दोनों मिलाएँ।
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