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What is the common ratio in the sequence (125,25,5,1,\ldots)?अनुक्रम (125,25,5,1,\ldots) में सामान्य अनुपात क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{1}{5})(\frac{1}{5})
The ratio of consecutive terms is (25\div125=\frac{1}{5}). In exams a decreasing geometric progression can have a fractional ratio.लगातार पदों का अनुपात (25\div125=\frac{1}{5}) है। परीक्षा में घटती गुणोत्तर श्रेणी में अनुपात भिन्न हो सकता है।
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