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Class 9MathematicsSequences and ProgressionsGeometric ProgressionEasyLevel 57
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What is the common ratio in the sequence (125,25,5,1,\ldots)?

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Answer and explanation

Correct answer: (\frac{1}{5})

The ratio of consecutive terms is (25\div125=\frac{1}{5}). In exams a decreasing geometric progression can have a fractional ratio.

Related tags

SequencesProgressionsGeometric-ProgressionClass-9Easy

Frequently asked questions

What is the correct answer to this question?

(\frac{1}{5})

Why is this the correct answer?

The ratio of consecutive terms is (25\div125=\frac{1}{5}). In exams a decreasing geometric progression can have a fractional ratio.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Geometric Progression.

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  1. 1Which sequence is formed by a multiplication rule, not an addition rule?
  2. 2What is the 7th term of (4, 12, 36, 108, ...)?
  3. 3In the sequence \((81,27,9,3,\ldots)\), each term is \(\frac{1}{3}\) of the previous term. What is the sixth term?
  4. 4In the sequence \((13,18,23,28,\ldots)\), which term is 98?
  5. 5In the sequence 3, 6, 12, 24, ..., which is the first term greater than 500?
  6. 6What is the common ratio in the sequence (2, 6, 18, 54, ...)?
  7. 7What will be the next term of the geometric progression (5,10,20,40,\ldots)?
  8. 8If a geometric progression has first term (4) and common ratio (2), what is the second term?
  9. 9What is the common ratio in the sequence (81,27,9,3,\ldots)?
  10. 10Is the sequence (3, 6, 12, 24, ...) a geometric progression?
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