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What is the common ratio in the geometric progression (32,16,8,4,\ldots)?गुणोत्तर श्रेणी (32,16,8,4,\ldots) में सामान्य अनुपात क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{1}{2})(\frac{1}{2})
The ratio of consecutive terms is (16\div32=\frac{1}{2}). In exams, write the fractional ratio for a decreasing geometric progression.लगातार पदों का अनुपात (16\div32=\frac{1}{2}) है। परीक्षा में घटती गुणोत्तर श्रेणी में भिन्न अनुपात लिखें।
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