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The first of (3) consecutive integers is (n). Which expression represents their sum?(3) लगातार पूर्णांकों में पहला (n) है। उनका योग किस व्यंजक से दर्शेगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(3n+3\)\(3n+3\)
If the first integer is \(n\), the three consecutive integers are \(n\), \(n+1\), and \(n+2\). Their sum is \(n+(n+1)+(n+2)=3n+3\). In \(3n+1\), the constant term is incorrect. Exam tip: Write consecutive numbers explicitly before adding them.यदि पहला पूर्णांक \(n\) है, तो तीन लगातार पूर्णांक \(n\), \(n+1\) और \(n+2\) होंगे। उनका योग \(n+(n+1)+(n+2)=3n+3\) है। \(3n+1\) में स्थिर पद सही नहीं है। परीक्षा टिप: लगातार संख्याओं को लिखकर जोड़ने से ऐसे व्यंजक आसानी से बनते हैं।
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