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In (x^2+kx+16), if the coefficient of (x) is (12), what is the value of (k-5)?

Answer and explanation

Correct answer: \(7\)

In \(x^2+kx+16\), the term containing \(x\) is \(kx\). The coefficient of \(x\) in this term is \(k\). Since the coefficient of \(x\) is given as \(12\), \(k=12\). Therefore, \(k-5=12-5=7\). Option \(12\) is the value of \(k\), not of \(k-5\). Exam tip: identify the factor multiplying the variable to find its coefficient.

Related tags

Algebraic ExpressionsPolynomialsCoefficientParameterLinear TermIntroduction To PolynomialsMathematicsClass 9 Mcq

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