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In the geometric progression (120,40,\frac{40}{3},\frac{40}{9},\ldots), which term is (\frac{40}{81})?गुणोत्तर श्रेणी (120,40,\frac{40}{3},\frac{40}{9},\ldots) में (\frac{40}{81}) कौन-सा पद है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (6)th termछठा पद
Each term is multiplied by (\frac{1}{3}), and the sixth term is (\frac{40}{81}). In exams, fractional terms can also be checked in order.हर बार (\frac{1}{3}) से गुणा होता है और छठा पद (\frac{40}{81}) आता है। परीक्षा में भिन्न पदों को क्रम से भी जाँच सकते हैं।
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