गुणोत्तर श्रेणी \(120,40,\frac{40}{3},\frac{40}{9},\ldots\) में \(\frac{40}{81}\) कौन-सा पद है?
In the geometric progression \(120,40,\frac{40}{3},\frac{40}{9},\ldots\), which term is \(\frac{40}{81}\)?
Explanation opens after your attempt
Correct Answer
A. छठा पद(6)th term
Concept
Each term is multiplied by \(\frac{1}{3}\), and the sixth term is \(\frac{40}{81}\). In exams, fractional terms can also be checked in order.
Why this answer is correct
The correct answer is A. छठा पद / (6)th term. Each term is multiplied by \(\frac{1}{3}\), and the sixth term is \(\frac{40}{81}\). In exams, fractional terms can also be checked in order.
Exam Tip
हर बार \(\frac{1}{3}\) से गुणा होता है और छठा पद \(\frac{40}{81}\) आता है। परीक्षा में भिन्न पदों को क्रम से भी जाँच सकते हैं।
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