यदि (x=-4), तो \(\frac{x^3-2x^2+8}{x}\) का मान क्या होगा?

If (x=-4), what is the value of \(\frac{x^3-2x^2+8}{x}\)?

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Explanation opens after your attempt
Correct Answer

B. (22)

Step 1

Concept

The numerator is ((-64)-2(16)+8=-88). Then \(\frac{-88}{-4}=22\).

Step 2

Why this answer is correct

The correct answer is B. (22). The numerator is ((-64)-2(16)+8=-88). Then \(\frac{-88}{-4}=22\).

Step 3

Exam Tip

अंश ((-64)-2(16)+8=-88) है। \(\frac{-88}{-4}=22\) मिलेगा।

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यदि (x=-4), तो \(\frac{x^3-2x^2+8}{x}\) का मान क्या होगा? / If (x=-4), what is the value of \(\frac{x^3-2x^2+8}{x}\)?

Correct Answer: B. (22). Explanation: अंश ((-64)-2(16)+8=-88) है। \(\frac{-88}{-4}=22\) मिलेगा। / The numerator is ((-64)-2(16)+8=-88). Then \(\frac{-88}{-4}=22\).

Which concept should I revise for this Mathematics MCQ?

The numerator is ((-64)-2(16)+8=-88). Then \(\frac{-88}{-4}=22\).

What exam hint can help solve this Mathematics question?

अंश ((-64)-2(16)+8=-88) है। \(\frac{-88}{-4}=22\) मिलेगा।