यदि (x=-4), तो \(\frac{x^3-2x^2+8}{x}\) का मान क्या होगा?
If (x=-4), what is the value of \(\frac{x^3-2x^2+8}{x}\)?
Explanation opens after your attempt
B. (22)
Concept
The numerator is ((-64)-2(16)+8=-88). Then \(\frac{-88}{-4}=22\).
Why this answer is correct
The correct answer is B. (22). The numerator is ((-64)-2(16)+8=-88). Then \(\frac{-88}{-4}=22\).
Exam Tip
अंश ((-64)-2(16)+8=-88) है। \(\frac{-88}{-4}=22\) मिलेगा।
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