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If (x=-3) and (y=2), what is the value of (x^2y+xy^2)?यदि (x=-3) और (y=2), तो (x^2y+xy^2) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 66
Substituting the given values, \(x^2y=(-3)^2\times2=9\times2=18\) and \(xy^2=(-3)\times2^2=(-3)\times4=-12\). Hence, \(x^2y+xy^2=18+(-12)=6\). The distractor \(-6\) may result from handling the sign of the negative term incorrectly. Exam tip: write a negative number in brackets before squaring it; \((-3)^2=9\).दिए गए मान रखने पर, \(x^2y=(-3)^2\times2=9\times2=18\) तथा \(xy^2=(-3)\times2^2=(-3)\times4=-12\)। अतः \(x^2y+xy^2=18+(-12)=6\)। विकल्प \(-6\) तब मिल सकता है जब ऋणात्मक पद के चिह्न को गलत ढंग से जोड़ा जाए। परीक्षा टिप: ऋणात्मक संख्या का वर्ग करने के लिए उसे कोष्ठक में लिखें, जैसे \((-3)^2=9\)।
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