यदि (x=-1), (y=2), तो \(x^2y^2-2xy\) का मान क्या होगा?

If (x=-1), (y=2), what is the value of \(x^2y^2-2xy\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (8)

Step 1

Concept

\(x^2y^2=1\cdot4=4\) and (2xy=2(-1)(2)=-4). Therefore, (4-(-4)=8).

Step 2

Why this answer is correct

The correct answer is C. (8). \(x^2y^2=1\cdot4=4\) and (2xy=2(-1)(2)=-4). Therefore, (4-(-4)=8).

Step 3

Exam Tip

\(x^2y^2=1\cdot4=4\) और (2xy=2(-1)(2)=-4)। इसलिए (4-(-4)=8)।

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Mathematics Answer, Explanation and Revision Hints

यदि (x=-1), (y=2), तो \(x^2y^2-2xy\) का मान क्या होगा? / If (x=-1), (y=2), what is the value of \(x^2y^2-2xy\)?

Correct Answer: C. (8). Explanation: \(x^2y^2=1\cdot4=4\) और (2xy=2(-1)(2)=-4)। इसलिए (4-(-4)=8)। / \(x^2y^2=1\cdot4=4\) and (2xy=2(-1)(2)=-4). Therefore, (4-(-4)=8).

Which concept should I revise for this Mathematics MCQ?

\(x^2y^2=1\cdot4=4\) and (2xy=2(-1)(2)=-4). Therefore, (4-(-4)=8).

What exam hint can help solve this Mathematics question?

\(x^2y^2=1\cdot4=4\) और (2xy=2(-1)(2)=-4)। इसलिए (4-(-4)=8)।