यदि (x=-1), (y=2), तो \(x^2y^2-2xy\) का मान क्या होगा?
If (x=-1), (y=2), what is the value of \(x^2y^2-2xy\)?
Explanation opens after your attempt
C. (8)
Concept
\(x^2y^2=1\cdot4=4\) and (2xy=2(-1)(2)=-4). Therefore, (4-(-4)=8).
Why this answer is correct
The correct answer is C. (8). \(x^2y^2=1\cdot4=4\) and (2xy=2(-1)(2)=-4). Therefore, (4-(-4)=8).
Exam Tip
\(x^2y^2=1\cdot4=4\) और (2xy=2(-1)(2)=-4)। इसलिए (4-(-4)=8)।
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