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If (u=-1) and (v=3), what is the value of (u^2v-uv^2+2u)?

Answer and explanation

Correct answer: 10

Substituting the values, \(u^2v=(-1)^2\times3=3\), \(uv^2=(-1)\times3^2=-9\), and \(2u=2\times(-1)=-2\). Hence, \(u^2v-uv^2+2u=3-(-9)-2=3+9-2=10\). Therefore, 10 is correct. The value 12 would result from omitting the term \(2u=-2\). Exam tip: when subtracting a negative term, remember that \(-(-9)=+9\).

Related tags

Algebraic ExpressionsSubstitutionInteger OperationsPolynomialsVariablesIntroduction To PolynomialsMathematicsClass 9 Mcq

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