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If (u=1) and (v=-2), what is the value of (4u+v^2)?

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Answer and explanation

Correct answer: 8

Substituting u=1 and v=-2, \(4u+v^2=4(1)+(-2)^2=4+4=8\). Therefore, the correct answer is 8. A common error is getting 6 by treating \((-2)^2\) as -4; the square of a negative number is positive. Exam tip: Always use brackets when squaring a negative number.

Related tags

Algebraic ExpressionsSubstitutionExponentsIntegersPolynomials

Frequently asked questions

What is the correct answer to this question?

8

Why is this the correct answer?

Substituting u=1 and v=-2, \(4u+v^2=4(1)+(-2)^2=4+4=8\). Therefore, the correct answer is 8. A common error is getting 6 by treating \((-2)^2\) as -4; the square of a negative number is positive. Exam tip: Always use brackets when squaring a negative number.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Algebraic expressions.

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