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If a geometric progression has (a_3=45) and (r=3), what is (a_1)?यदि गुणोत्तर श्रेढ़ी में (a_3=45) और (r=3) है, तो (a_1) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 55
In a geometric progression, the third term is \(a_3=a_1r^2\). Thus, \(45=a_1\times 3^2=9a_1\), so \(a_1=45/9=5\). Option 15 is the second term \(a_2\), since \(5\times3=15\). Exam tip: use \(a_n=a_1r^{n-1}\) for the nth term of a GP.गुणोत्तर श्रेणी में तीसरा पद \,\(a_3=a_1r^2\) होता है। अतः \(45=a_1\times 3^2=9a_1\), इसलिए \(a_1=45/9=5\)। विकल्प 15 दूसरा पद \(a_2\) होगा, क्योंकि \(5\times3=15\)। परीक्षा टिप: \(n\)वाँ पद निकालने के लिए \(a_n=a_1r^{n-1}\) सूत्र याद रखें।
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