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If \(a=6\) and \(r=2\), what is the fourth term of the geometric progression?
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Answer and explanation
Correct answer: 48
The \(n\)th term of a geometric progression is \(T_n=ar^{n-1}\). Hence, \(T_4=6\times2^{4-1}=6\times2^3=48\). The value 24 is the third term, since \(T_3=6\times2^2=24\). Exam tip: the exponent of the common ratio in the \(n\)th term is always \(n-1\).
Frequently asked questions
What is the correct answer to this question?
48
Why is this the correct answer?
The \(n\)th term of a geometric progression is \(T_n=ar^{n-1}\). Hence, \(T_4=6\times2^{4-1}=6\times2^3=48\). The value 24 is the third term, since \(T_3=6\times2^2=24\). Exam tip: the exponent of the common ratio in the \(n\)th term is always \(n-1\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Geometric Progression.
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